Y=x^2-5x+12

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Solution for Y=x^2-5x+12 equation:



=Y^2-5Y+12
We move all terms to the left:
-(Y^2-5Y+12)=0
We get rid of parentheses
-Y^2+5Y-12=0
We add all the numbers together, and all the variables
-1Y^2+5Y-12=0
a = -1; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·(-1)·(-12)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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